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Pranav
- Rate $14
- Response 1h

$14/hr
1st lesson free
- Maths
- Algebra
- Trigonometry
- Chemistry
- Linear Algebra
Easy question solving and doubt solving plus explanation any time you ask for.
- Maths
- Algebra
- Trigonometry
- Chemistry
- Linear Algebra
Lesson location
Recommended
Pranav is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. An excellent choice to progress with confidence.
About Pranav
I am a Btech student from government college, and I want to share all the information I have with every single one of you who needs it, as this is the time when each and every person becomes knowledgeable. With my good method of teaching I would make it very easy for everyone to gain interest in the particular subject.
About the lesson
- High School
- NCEA Level 1
- NCEA Level 2
- +2
levels :
High School
NCEA Level 1
NCEA Level 2
NCEA Level 3
Primary
- English
All languages in which the lesson is available :
English
The way you all will be explained your doubts will be way different from other teachers, as I am going to explain every question step by step which you would surely find interesting. The way I wanted my teachers to explain me so that I could understand everything will be the way I will be teaching you all.
Recommendations
Recommendations come from relatives, friends and acquaintances of the teacher
Pranav is a extraordinarily good at mathematics and quite quick with calculations.
Additionally he has great teaching skills and can be a really good tutor.He tries to connect with real life examples which help to grasp complex concept easily . A good problem solver and he also let u know the most optimized way for a particular problem.
He is dedicated to his work and do his work with honesty. He has a great problem solving skills.
View more recommendations
Rates
Rate
- $14
Pack prices
- 5h: $44
- 10h: $114
free lessons
The first lesson with Pranav will allow you to get to know each other and discuss your needs for future lessons.
- 1hr
online
- $-4/h
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